How to calculate surface area of a cube with volume

How to calculate surface area of a cube with volume?

This is a very common question asked in maths exams. The surface area of a cube is рS = 6 l², where l is the length of one side of the cube. This means that the surface area of one face, the front or the base, is equal to the length of each side multiplied by 6.

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How to calculate surface area of cube with given volume?

The surface area of a cube is equal to the sum of the areas of its six faces. The surface area of a cube with sides equal to length L is equal to 6L2. To find the surface area of a cube with an unknown volume, take the cube's volume and divide it by the cube's base length (L). If the result is a whole number, then the surface area of the cube is equal to the number you obtained. If the result is not a whole number,

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How to calculate the surface area of a cube with given volume?

First, you need to find the area of one side of the cube. This is simply its length multiplied by its width and height. This gives you the base of the cube. You then need to add the sum of the areas of the faces onto it. To do this, you need to use the Pythagorean Theorem. Once you have this number, you can find the surface area of the cube by multiplying the base by the number of faces. This process is shown in the figure below

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How do you calculate surface area of a cube with volume?

If you already know the length of each edge of the cube, you can use the Pythagorean Theorem and the volume to find the surface area. You can use the formula A = sqrt((l1)^2 + (l2)^2 + (l3)^2), where l1, l2, and l3 are the lengths of each edge. Using this method, you can easily find the surface area of a cube with volume.

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How to calculate the surface area of a cube with volume?

You can find the surface area of a cube (or any other solid shape) using the following formula: V multiplied by the surface area of the unit cube. The unit cube has a surface area of 1 square. So, the surface area of any cube with an area of V must be equal to V.

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